[SQL] 즐겨찾기가 가장 많은 식당 정보 출력하기

Created by

무둥

Created at

Apr 15, 2025 8:48 AM

◇ 내 답변

-- 코드를 입력하세요
SELECT FOOD_TYPE, REST_ID, REST_NAME, FAVORITES
FROM REST_INFO
WHERE (FOOD_TYPE,FAVORITES) 
IN 
(
    SELECT FOOD_TYPE, MAX(FAVORITES) 
    FROM REST_INFO
    GROUP BY FOOD_TYPE
)
ORDER BY FOOD_TYPE DESC;

서브쿼리를 단박에 생각해내는게 어렵다 하... ㄱ-

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